Integrand size = 15, antiderivative size = 266 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {3 d \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{16 a^{5/2} \sqrt {b}}-\frac {21 c \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}-\frac {21 c \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}} \]
[Out]
Time = 0.15 (sec) , antiderivative size = 266, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.667, Rules used = {1869, 1890, 217, 1179, 642, 1176, 631, 210, 281, 211} \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=-\frac {21 c \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \arctan \left (\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}+1\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {3 d \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{16 a^{5/2} \sqrt {b}}-\frac {21 c \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {a}+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {a}+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {x (c+d x)}{8 a \left (a+b x^4\right )^2} \]
[In]
[Out]
Rule 210
Rule 211
Rule 217
Rule 281
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1869
Rule 1890
Rubi steps \begin{align*} \text {integral}& = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}-\frac {\int \frac {-7 c-6 d x}{\left (a+b x^4\right )^2} \, dx}{8 a} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {\int \frac {21 c+12 d x}{a+b x^4} \, dx}{32 a^2} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {\int \left (\frac {21 c}{a+b x^4}+\frac {12 d x}{a+b x^4}\right ) \, dx}{32 a^2} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {(21 c) \int \frac {1}{a+b x^4} \, dx}{32 a^2}+\frac {(3 d) \int \frac {x}{a+b x^4} \, dx}{8 a^2} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {(21 c) \int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx}{64 a^{5/2}}+\frac {(21 c) \int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx}{64 a^{5/2}}+\frac {(3 d) \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,x^2\right )}{16 a^2} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {3 d \tan ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{16 a^{5/2} \sqrt {b}}+\frac {(21 c) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx}{128 a^{5/2} \sqrt {b}}+\frac {(21 c) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx}{128 a^{5/2} \sqrt {b}}-\frac {(21 c) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}-\frac {(21 c) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {3 d \tan ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{16 a^{5/2} \sqrt {b}}-\frac {21 c \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {(21 c) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}-\frac {(21 c) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}} \\ & = \frac {x (c+d x)}{8 a \left (a+b x^4\right )^2}+\frac {x (7 c+6 d x)}{32 a^2 \left (a+b x^4\right )}+\frac {3 d \tan ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )}{16 a^{5/2} \sqrt {b}}-\frac {21 c \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{64 \sqrt {2} a^{11/4} \sqrt [4]{b}}-\frac {21 c \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}}+\frac {21 c \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{128 \sqrt {2} a^{11/4} \sqrt [4]{b}} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 249, normalized size of antiderivative = 0.94 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\frac {\frac {32 a^{7/4} x (c+d x)}{\left (a+b x^4\right )^2}+\frac {8 a^{3/4} x (7 c+6 d x)}{a+b x^4}-\frac {6 \left (7 \sqrt {2} \sqrt [4]{b} c+8 \sqrt [4]{a} d\right ) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{\sqrt {b}}+\frac {6 \left (7 \sqrt {2} \sqrt [4]{b} c-8 \sqrt [4]{a} d\right ) \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} x}{\sqrt [4]{a}}\right )}{\sqrt {b}}-\frac {21 \sqrt {2} c \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{\sqrt [4]{b}}+\frac {21 \sqrt {2} c \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} x+\sqrt {b} x^2\right )}{\sqrt [4]{b}}}{256 a^{11/4}} \]
[In]
[Out]
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 1.48 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.32
method | result | size |
risch | \(\frac {\frac {3 b d \,x^{6}}{16 a^{2}}+\frac {7 b c \,x^{5}}{32 a^{2}}+\frac {5 d \,x^{2}}{16 a}+\frac {11 c x}{32 a}}{\left (b \,x^{4}+a \right )^{2}}+\frac {3 \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (\textit {\_Z}^{4} b +a \right )}{\sum }\frac {\left (4 \textit {\_R} d +7 c \right ) \ln \left (x -\textit {\_R} \right )}{\textit {\_R}^{3}}\right )}{128 a^{2} b}\) | \(86\) |
default | \(c \left (\frac {x}{8 a \left (b \,x^{4}+a \right )^{2}}+\frac {\frac {7 x}{32 a \left (b \,x^{4}+a \right )}+\frac {21 \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x^{2}+\left (\frac {a}{b}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{b}}}{x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{4}} x \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{256 a^{2}}}{a}\right )+d \left (\frac {x^{2}}{8 a \left (b \,x^{4}+a \right )^{2}}+\frac {\frac {3 x^{2}}{16 a \left (b \,x^{4}+a \right )}+\frac {3 \arctan \left (x^{2} \sqrt {\frac {b}{a}}\right )}{16 a \sqrt {a b}}}{a}\right )\) | \(207\) |
[In]
[Out]
Result contains complex when optimal does not.
Time = 2.19 (sec) , antiderivative size = 43180, normalized size of antiderivative = 162.33 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\text {Too large to display} \]
[In]
[Out]
Time = 1.14 (sec) , antiderivative size = 192, normalized size of antiderivative = 0.72 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\operatorname {RootSum} {\left (268435456 t^{4} a^{11} b^{2} + 4718592 t^{2} a^{6} b d^{2} - 2709504 t a^{3} b c^{2} d + 20736 a d^{4} + 194481 b c^{4}, \left ( t \mapsto t \log {\left (x + \frac {- 67108864 t^{3} a^{9} b d^{2} - 9633792 t^{2} a^{6} b c^{2} d - 589824 t a^{4} d^{4} - 2765952 t a^{3} b c^{4} + 423360 a c^{2} d^{3}}{193536 a c d^{4} - 453789 b c^{5}} \right )} \right )\right )} + \frac {11 a c x + 10 a d x^{2} + 7 b c x^{5} + 6 b d x^{6}}{32 a^{4} + 64 a^{3} b x^{4} + 32 a^{2} b^{2} x^{8}} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 269, normalized size of antiderivative = 1.01 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\frac {6 \, b d x^{6} + 7 \, b c x^{5} + 10 \, a d x^{2} + 11 \, a c x}{32 \, {\left (a^{2} b^{2} x^{8} + 2 \, a^{3} b x^{4} + a^{4}\right )}} + \frac {3 \, {\left (\frac {7 \, \sqrt {2} c \log \left (\sqrt {b} x^{2} + \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {7 \, \sqrt {2} c \log \left (\sqrt {b} x^{2} - \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}} + \frac {2 \, {\left (7 \, \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} c - 8 \, \sqrt {a} d\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {b} x + \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{a^{\frac {3}{4}} \sqrt {\sqrt {a} \sqrt {b}} b^{\frac {1}{4}}} + \frac {2 \, {\left (7 \, \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} c + 8 \, \sqrt {a} d\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {b} x - \sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{a^{\frac {3}{4}} \sqrt {\sqrt {a} \sqrt {b}} b^{\frac {1}{4}}}\right )}}{256 \, a^{2}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 256, normalized size of antiderivative = 0.96 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\frac {21 \, \sqrt {2} \left (a b^{3}\right )^{\frac {1}{4}} c \log \left (x^{2} + \sqrt {2} x \left (\frac {a}{b}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{b}}\right )}{256 \, a^{3} b} - \frac {21 \, \sqrt {2} \left (a b^{3}\right )^{\frac {1}{4}} c \log \left (x^{2} - \sqrt {2} x \left (\frac {a}{b}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{b}}\right )}{256 \, a^{3} b} + \frac {3 \, \sqrt {2} {\left (4 \, \sqrt {2} \sqrt {a b} b d + 7 \, \left (a b^{3}\right )^{\frac {1}{4}} b c\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x + \sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{128 \, a^{3} b^{2}} + \frac {3 \, \sqrt {2} {\left (4 \, \sqrt {2} \sqrt {a b} b d + 7 \, \left (a b^{3}\right )^{\frac {1}{4}} b c\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x - \sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{128 \, a^{3} b^{2}} + \frac {6 \, b d x^{6} + 7 \, b c x^{5} + 10 \, a d x^{2} + 11 \, a c x}{32 \, {\left (b x^{4} + a\right )}^{2} a^{2}} \]
[In]
[Out]
Time = 9.42 (sec) , antiderivative size = 315, normalized size of antiderivative = 1.18 \[ \int \frac {c+d x}{\left (a+b x^4\right )^3} \, dx=\frac {\frac {5\,d\,x^2}{16\,a}+\frac {11\,c\,x}{32\,a}+\frac {7\,b\,c\,x^5}{32\,a^2}+\frac {3\,b\,d\,x^6}{16\,a^2}}{a^2+2\,a\,b\,x^4+b^2\,x^8}+\left (\sum _{k=1}^4\ln \left (\frac {b^2\,\left (63\,c\,d^2+36\,d^3\,x-{\mathrm {root}\left (268435456\,a^{11}\,b^2\,z^4+4718592\,a^6\,b\,d^2\,z^2-2709504\,a^3\,b\,c^2\,d\,z+194481\,b\,c^4+20736\,a\,d^4,z,k\right )}^2\,a^5\,b\,c\,7168-\mathrm {root}\left (268435456\,a^{11}\,b^2\,z^4+4718592\,a^6\,b\,d^2\,z^2-2709504\,a^3\,b\,c^2\,d\,z+194481\,b\,c^4+20736\,a\,d^4,z,k\right )\,a^2\,b\,c^2\,x\,1176+{\mathrm {root}\left (268435456\,a^{11}\,b^2\,z^4+4718592\,a^6\,b\,d^2\,z^2-2709504\,a^3\,b\,c^2\,d\,z+194481\,b\,c^4+20736\,a\,d^4,z,k\right )}^2\,a^5\,b\,d\,x\,4096\right )\,3}{a^6\,2048}\right )\,\mathrm {root}\left (268435456\,a^{11}\,b^2\,z^4+4718592\,a^6\,b\,d^2\,z^2-2709504\,a^3\,b\,c^2\,d\,z+194481\,b\,c^4+20736\,a\,d^4,z,k\right )\right ) \]
[In]
[Out]